$\frac{dy}{dx}=\frac{y}{x}+\:1$
$8-\left(-37+18-47\right)+12-10$
$x^3+3xy$
$12x-1<3$
$1=\log_{36}\left(x\right)+\log_{36}\left(-20-x\right)$
$\left(1^4\right)^{\sqrt{3}}$
$\left(pq\:+\:4\right)\:\left(pq\:-\:6\right)$
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