$\frac{-3}{-3}$
$\left(3a+2b\right)\left(9a^2-6ab+4b^2\right)$
$-6x+3y=36$
$2cos\left(\frac{x}{4}\right)=\sqrt{2}$
$5-x+xy-3yx-2+2x$
$\int_{\frac{\pi}{3}}^{\frac{\pi}{3}}\left(3x+\pi\right)cos3xdx$
$x^2+4x+14$
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