$y^2+18y$
$-495+65$
$\left(-4s-6h\right)^2$
$4x^2-16y^2$
$o^2+16o+1$
$\ln\left(x+7\right)-\ln x=2$
$\frac{\left(1-cos\left(4x\right)\right)}{2}=sin^4x$
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