$\int5\sec\left(3x^2-4\right)xdx$

$2x^2y\:dx\:+\left(2x^3y^2+8y^2x\right)\:dy\:=0$

$\left(-03\right)\left(-40\right)\left(50\right)$

$+6m^2n+-4m^2n+-2m^2n$

$\int\frac{1}{\left(240-x\right)\left(160-3x\right)}dx$

$\int\frac{5x^5+3x^3-x}{x}dx$

$\frac{dy}{dx}=5x\left(y-3\right)^2$