$\frac{d}{dx}xy-3x+4x^2=7$
$\frac{x^3-2x+4}{3x^2-1}$
$4.58+4.83$
$9a+10b-6c=-46$
$\left(y+\frac{13}{5}\right)\left(y-\frac{13}{5}\right)$
$\left(x-1\right)\left(x+5\right)\left(x-4\right)$
$2x+4<10$
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