$2x+3>4$
$\left(2x^3+5x+3\right)+\left(4x-3x^2+2x^3\right)$
$13-\sqrt{64}\cdot\left(7^2\left(3-6\right)+2\right)$
$\left(a^{-2}\right)^{-4}\cdot\:2a^{-2}$
$-\left(8+9\right)-\left[2-5-\left(3-7\right)\right]$
$2v^2+11v+15$
$\frac{3}{5}\left(\frac{2y+4}{5}\right)$
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