$24-2\cdot7-5\cdot8$
$74\cdot66$
$\sqrt{12\cdot x^3\cdot y^5}\cdot z^2$
$\lim_{x\to0}\left(\arcsec\left(\frac{\left(4-4\cos\left(x\right)\right)}{\sqrt{3}x^2}\right)\right)$
$x^2+2x-6>0$
$3=x$
$\lim_{x\to\infty}\left(x^3-3x^2\right)$
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