$\left(4x^3-2x^2-5\right)-\left(-x^4+x^2-3\right)$

$\frac{x^4-5x+4}{x-5}$

$+\left(-4.1\right)\left(-1.2\right)$

$\frac{dy}{dx}=\frac{\left(y\right)^{\frac{1}{2}}}{e^{2x}}$

$\sqrt{\left(x^2-2x-3\right)^2}\le\:5\sqrt{\left(x^2-4x-3\right)^2}$

$a+-b+0$

$\frac{\left(m^2\right)}{m^5.m^4}^4$