$\frac{\left(x^2+2\right)}{x}$
$-4\left(x-2\right)-3>2\left(x+4\right)$
$\lim_{x\to2}\left(\frac{x^3-3x+2}{x^2-x-6}\right)$
$\frac{2x^2+x-2}{x}$
$\frac{x^2-13x+39}{x-6}$
$15abc^2-45abc$
$\left(x^2-6y\right)^2$
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