$16 \cdot 2 ^ { 3 } + 4 - 2$
$-x^2-8+65$
$1-21-20$
$-5<\frac{4-3x}{3}$
$\left(4a+5b^2\right)\left(4a-5b^2\right)$
$\ln\left(\frac{-9x-2}{x^2+12}\right)=0$
$x+10=20$
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