$\frac{x-5}{x+6}=\frac{4}{3}$
$3x^2+7x-4=0$
$xy'+\left(xy+y-x^2-2x\right)x'$
$7,5+2,73-19+3,8-59,6-10$
$16x-x$
$x^2-8x+9=0$
$-5-\left(05\right)+3-\left(-2\right)$
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