$c^2-2c-3$
$y'=\frac{x-y}{x}$
$3x^2\cdot\left(2x^3-3x^2+4x-2\right)$
$\lim_{x\to2}\left(4x^2+3\right)$
$\int_{0}^{\frac{\pi}{4}}\sec^{4}\thetad\theta$
$\frac { z } { 3 } = 17$
$f\left(x\right)=\left(x^2-4x\right)^x\:\left(2x\right)^2$
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