$\frac{dy}{dx}=\frac{y\:cosx}{1+y^2}$
$\int2x\cos\left(\frac{1}{2}x\right)dx$
$4m^3+20m^2+24$
$\frac{dy}{dx}=\sin\left(5x\right);y\left(0\right)=1$
$4x-12<-16$
$\int\:\left(\frac{3}{2x}-4x^5\right)\left(\frac{6}{5\sqrt[4]{x^3}}+\frac{2}{x^3}\right)dx$
$8\cdot5+7$
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