$-2x-4\left(4x-8\right)$
$4\:=\:4k\:+\:12$
$\int_1^3\left(3+5\left(x\right)\right)dx$
$\frac{8y^4}{4y^3}$
$3\left(6x+4\right)-12+2x$
$\left(-2x^{-3}\:y^4\right)^2$
$3cos\left(x+y\right)\:+\:3cos\left(x-y\right)=6cos\left(x\right)cos\left(y\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!