$\frac{2-x}{5}+\frac{x-3}{2}>1$
$\lim_{x\to\infty}\left(\frac{x}{11^x}\right)$
$\lim_{x\to0}\left(\frac{tan\left(sin\left(2x+1\right)\right)}{2x+1}\right)$
$x+5y=11$
$a^2-9a+14$
$5x^2+12x+3=0$
$\frac{dy}{dx}=\frac{-1}{y^2x^2}$
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