$x^3-4x^3$
$\left(5+x^2\right)\frac{dy}{dx}=\frac{x}{y}$
$\sin\left(x+1\right)=0$
$x<x^2+2x+1$
$\:\frac{4x-6}{6\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}\le-5$
$\left(2x-\frac{1}{3}\right)^{2}$
$-40\cdot2-5$
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