$\left(7d-4g\right)^2$
$2x^2\:+\:5x\:+\:6\:<0$
$\frac{dy}{dx}=5x^4$
$\lim\:_{x\to\:0}\left(\left(e^{2x}-x\right)^{\frac{1}{2x}}\right)$
$3^2\cdot3^5\cdot3$
$x^2-8x+8\:>4-4x$
$\left(\frac{\sqrt{1+x^2}}{1+y}\right)\frac{dy}{dx}=-x$
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