$-1\:-1\:+6\:+1$
$\frac{1}{4}y'-x^2=0$
$0.04x^2\:-\:0.28x\:+\:0.49$
$\left(3mn^2-5\right)\left(3mn^2-6\right)$
$^{x^2}+4x+5x+x^2$
$-396+6$
$e^xy\:\frac{dy}{dx}=e^{-y}+xe^{-3x-y}$
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