$\lim_{x\to0}\left(\frac{\sin\left(2x^2\right)}{\tan^2\left(3x\right)}\right)$
$\left(\sqrt[2]{x^2+1}\right)^x$
$\frac{1}{4x-16}$
$-5x^2\cdot3x^3+2x^2-3x+4$
$\int\frac{5x-1}{x^2-2x-8}dx$
$-3\cdot19$
$4x\left(x^2+9x\right)$
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