$\left(x-2\right)<x+1$
$-4x^3y-4xy^3+5;\:x=2;\:y=-1$
$\lim_{x\to3}\left(\frac{2x^2+\:12x-\:18}{x^2+\:x-6}\right)$
$a+9<12$
$\left(y+6\right)\left(y-4\right)$
$\lim_{x\to0}\frac{1}{x\csc x}$
$\frac{x-1}{1-2x}+\frac{4}{x+4}=0$
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