$\frac{2}{3}x^4+\frac{8}{6}x^3-\frac{10}{12}x^4+x^6$
$\lim_{x\to\infty}\left(4ln\left(x^2+1\right)-4ln\left(x+1\right)\right)$
$n^2-36$
$-1+-13+-3+2$
$4x-7\cdot x+2$
$2x^3-2x$
$m^2+12^2$
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