$x^2+5x-10=0$
$1\:+12x\:+36x^2$
$\lim_{x\to1}\left(\frac{s^3-1}{s^2-1}\right)$
$y=-\frac{3}{4}x-1$
$-7-3-5-2-12-6-9-5$
$9b+5b-8$
$\left(2a+12\right)^2$
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