$\left(-19\right)-\left(-22\right)$

$\int\left(\sec\left(4x\right)+\tan\left(4x\right)\right)^2dx$

$2^5.\:7^5$

$4^2-4$

$\left(5x^2-6x\right)-\left(4x^2-3x+m^3\right)$

$\lim_{x\to infinity}\left(\frac{arctan\left(x^4\right)}{x^3}\right)$

$8a+12+\left(-9\right)-\left(-6a\right)$