$\frac{a^3-27b^3}{3a-9b}$
$\frac{\left(x^3+2x^2+61\right)}{\left(x+3\right)^2\left(x^2+4\right)}$
$\left(x^2+10x+9\right)\cdot\left(3x+4\right)$
$17-0,5\left(1\right)$
$\lim_{x\to\infty}\left(e^{\frac{3}{x}}\right)$
$5x^3+5x^3$
$\lim_{x\to0}\left(\frac{sin4x}{x+x^2}\right)$
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