$-3x^2+12=-5x^2+20$
$\sqrt{x}x\sqrt[3]{2^2}$
$x^{3\:}-3x^2+5x-6$
$12ax^2-27a$
$6y^5-17y^4$
$\left(a+5\right)\left(a-5\right)-a\left(a-1\right)$
$\frac{2\sin^2\left(x\right)+\cos2\left(x\right)}{\sec\left(x\right)}=\cos\left(x\right)$
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