$x^2\le10-3x$
$5x+29=9x-15$
$\int x\:^{10}dx$
$-4x+9y=18$
$\int4x^3e^{x^4-6}dx$
$\left(\left(\frac{45.02171}{18.17}\right)-1\right)\cdot100$
$3^2\:-\sqrt{10.000}$
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