$\left(\frac{1}{2}x^2y+5\right)\cdot\left(\frac{1}{2}x^2y-5\right)$
$-x^2+7x-20$
$-\left(23-45\right)-\left(75-34\right)$
$\frac{\left(sec^2\theta\:-1\right)}{tan\theta\:}=tan\theta\:$
$24x^2-22x+5$
$\left(x+4\right)^2-\left(x+7\right)^2$
$x^6y^2-4x^3yz+4z^2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!