$2\:lnx\:^3$
$3x+1>=7x-2$
$\frac{\tan\left(3x-3y\right)}{\left(3x-3y\right)}$
$-12\:x\:5$
$\int\:\:12\left(y^4+4y^2+1\right)^2\left(y^3+2y\right)dy$
$\frac{\left(a-b\right)\left(a-b+c\right)b}{c\left(a-c\right)}.-1$
$-e^1$
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