$6\left(1-n\right)^2$
$4n+6+n-2$
$\left(9-3\right)+\left(2-7\right)$
$10\left(15-8\right)$
$\lim_{x\to\frac{2}{\pi}}\left(\frac{\tan x}{\tan5x}\right)$
$10\left(9-4x\right)-5\:\left(-3x+9\right)$
$-4=\frac{x}{5}+6$
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