$2x^2+3x-x^2-x$
$\left(4ab^2\right)\left(-7a^2b^3\right)$
$\int2^{3x+3}dx$
$\frac{1}{2}\cdot\log\left(49\right)=\log\left(x-5\right)$
$y'+2xy=4x$
$3a^2b\cdot2ab^2$
$46+2+\left(-1\right)+2$
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