$16\left(3+2\right)$
$0.0001\cdot\infty$
$\left(\frac{3^4}{3^2}\right)\left(\frac{3^2}{3^3}\right)\left(3^5\right)$
$\int\frac{x^{4}\sqrt[5]{\left(1-4x^{5}\right)^{3}}}{2}dx$
$\frac{\left(4x+1\right)}{x^2+x}$
$\left(b^{-4}c^4\right)^8$
$\frac{216-125w^3}{2a^3+y^3}$
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