$\frac{y^{12}}{y^3}$
$-4+\sec x=-6$
$1-\left(-15\times4y^{3}\right)\left(-16x^{2}y^{2}\right)$
$x\frac{dy}{dx}-4y=x^5\cdot e^{3x}$
$3w-5+1-6w$
$\frac{dy}{dx}=\frac{x+y^2x}{y}$
$2x^2-12x-3=0$
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