$\left(1-7x\right)\:\left(3x\:-1\right)$
$2x^2+3x-3<0$
$x^3+y^3=4$
$9\left(z+4\right)$
$2x^2+\frac{x}{3}=\frac{5x^2}{2}-3x+\frac{14}{5}$
$\lim_{x\to4}\left(x-4\right)$
$\int\left(2\sqrt{x+1}\right)-\left(-16+4x\right)dx$
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