$\frac{x^4}{-4}+4x^2-16$
$x^{2+40x+400}$
$\frac{1+\cot\left(a\right)}{1+\tan\left(a\right)}$
$2-\left(-8\right)-\left(+2\right)$
$\tan\left(x\right)\cdot\csc\left(x\right)-\sec\left(x\right)=0$
$\frac{x}{4}=\frac{x+2}{2}$
$5x^2+3x+2=0$
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