$\frac{1+\sec^{2}\theta}{\sec^{2}\theta}=1+\cos^{2}\theta$

$\left(\sqrt{6}\right)x\left(2\sqrt{3}y\right)^2$

$\int5\sqrt{3x-1}dx$

$x=6-y^2$

$\frac{dy}{dx}=\frac{1}{8}.\sqrt{x}$

$\int_{\frac{\pi}{6}}^{\frac{\pi}{6}}\left(\frac{\sin\:\left(6x\right)}{6}\right)dx$

$\left(\frac{26}{2}\right)^2$