$\int8\left(4x^2-5\right)^2xdx$
$\left(x+1\right)\left(x+4\right)$
$\lim_{z\to0}\:\frac{sen\left(z\right)^2}{z}$
$\int\frac{4}{4y-y^2}dy$
$\frac{6x-1}{6}\le17x$
$\frac{x}{-7}-3=1$
$2^5\cdot2^3\cdot2^2$
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