$6z^2+3z-18$
$6a+8c-10d+a-2c$
$-10x=-30$
$\frac{6x-7}{4}\ge-5$
$\left(5x+10y\right)\left(3x+6y\right)$
$\frac{d}{dx}\frac{4\sin\left(x\right)}{3\cos\left(x\right)}$
$12\csc\left(\frac{x}{4}\right)^2=4$
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