$-3\left(3y-4x\right)+2\left(5x+4y\right)$
$\frac{du}{dt}=e^{4u+6t}$
$\int\frac{3x^2-x+4}{x\left(x^3+2x^2+x\right)}dx$
$\left(4a^2b^3\right)\left(-3a^2b^2\right)\left(-2a^3b^2c^2\right)$
$\frac{x^2+2x-15}{x^3-1}$
$3x-8\left(2x+3\right)=-6\left(2x+5\right)$
$\left(x^4+8\right)\left(x^4-2\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!