$\frac{\left(1+\cos\:\left(x\right)\right)}{\sec\left(x\right)}$

$\frac{dy}{dx}=6x^3+4x$

$\:12\:\:+\:\:\left(\:-\:28\:\right)\:-\:\:\left(\:-\:17\:\right)\:\:+\:15$

$\left(\sqrt{2z^5}-6z^3+17z+\sqrt{6}\right)+\left(2^4+16z^3-5z+\sqrt{6}\right)$

$2b^2+5b-3=0$

$\frac{0.00000762939453125}{2}$

$x^{12}-y^{20}$