$2x+4\le10-x$
$u-u-u^2$
$\int\frac{x^2+\arctan\left(x\right)}{\sqrt{4-x^2}}dx$
$\int\:\frac{\:xe^{2x}}{\left(2x+1\right)^2}dx$
$\left(-15\right)\::\:\left(-1\right)$
$a^2+11a-26=0$
$-5-5+4+-4+4$
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