$-3x\le12$
$\frac{dy}{dt}=t^4y^2$
$4\sec\left(x\right)+\tan\left(x\right)$
$\frac{b}{6}+4\le3$
$-3<7-v$
$\left(-27\right)\cdot\left(-3\right)\cdot\left(-3\right)^2\cdot\left(-3\right)^0$
$\int\frac{\left(4x-1\right)}{x\left(x^2+4\right)\left(x-5\right)}dx$
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