$\frac{3}{x-4}+\frac{3}{x+4}=\frac{24}{x^2-16}$
$x^2-3x-2x+6$
$\frac{2\left(12.5x\right)}{4}$
$\lim_{x\to2}\left(\frac{3x-6}{3x-14}\right)$
$sin\left(x\right)sec\left(x\right)+csc\left(x\right)cos\left(x\right)=\:sec\left(x\right)csc\left(x\right)$
$\int2x\left(x^2+5\right)^{10}dx$
$\frac{x^6}{x^{-7}.\:x\:^{-8}}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!