$\sqrt{3}x\sqrt{9x}^2$
$-6x-4=\frac{1}{2}x-4$
$y'=6\sqrt{y}$
$\left(2x+2\right)\left(x-1\right)$
$m^2\:-\:225$
$\frac{3}{2x-8}+\frac{1}{4-x}=\frac{1}{2}$
$dt=\frac{1}{5}\left(t-20\right)dt$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!