$3\cos^2\left(x\right)-\cos\left(2x\right)=1$
$y-\ln\left(x\right)=0$
$\int e^8.x^2dx$
$\int_0^{\pi\:}t^2cos\left(nt\right)dt$
$18\:\cdot\:\left(-3\:-\:\left[\:\cdot\:\left(-3\right)\right]\right)$
$\left(4c-d\right)^2$
$y=\frac{sinxcos^2xtan^6x}{\sqrt{x}}$
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