$\left(0.1x+2y\right)^2$

$\frac{sin\left(x\right)}{1-cos\left(x\right)}+\frac{1-cos\left(x\right)}{sin\left(x\right)}=sec\left(x\right)$

$a^2b^2c^2-a^2e^2i^2$

$-5-\left[-3+2+\left(-8\right)\right]$

$y^3-2y^2-4y+8$

$f\left(x\right)=\frac{senx}{cosx}$

$cos\left(x\right)\cdot cos\left(2x\right)=\frac{sin\left(2x\right)}{4}$