$-3x^2+2x^4-8-x^3\:+5x-5x^4$
$\left(\sqrt{1-x^2}\right)y'=xy$
$\frac{3x+5}{x^2+3x+2}$
$m^3-12m+16$
$\left(m+n\right)^2\left(m^2-mn-n^2\right)$
$\left(3x+6\right)\left(x-9\right)$
$5-8+3-2\cdot\left(-8\right)$
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