$\int\sqrt{cos\left(4x\right)+1}dx$

$4\:+\:\left(-6\right)\:-\:4\:+\:\left(-8\right)\:-\:\left(-7\right)\:+\:\left(-11\right)\:+\:4\:-\:\left(-5\right)\:+\:\left(4\right)\:-\:\left(-3\right)\:+\:4\:-\:11$

$f\left(x\right)=2x^3+4x^2-6$

$\frac{49a^{2b}-100c^2}{9^{1b}+10c}$

$3.^4-2.^4+7.^4$

$\int_1^2e^xdx$

$\left(\frac{1}{6}m^2n-\frac{4}{3}mn^2\right)\left(-0666m^2n-1333mn^2\right)$