$\sqrt{2a^2}\cdot\sqrt{6a^2}$
$\int6\left(1+\tan^2\left(x\right)\right)dx$
$-11=-2+b$
$1-\frac{sinxtanx}{1+secx}=cosx$
$\left(x^4\:+\:y^4\right)dx\:-\:xy^3\:dy\:=\:0$
$-2x^3+x^2$
$sin^2\left(60\right)$
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