$\frac{dy}{\:dx}=e^{3x+2y}$
$x^2+2x^2y+3xy=0$
$\left(x-2\right)\left(x+5\right)\left(x+3\right)\left(x-4\right)$
$x^2-4x=-3$
$\frac{dy}{dx}=\frac{1}{\sqrt[3]{x+2}}$
$y'=0.072-0.24y-0.105e^{0.96t}$
$\int sen\:ax\:dx$
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