$\int x^{\frac{4}{3}}dx$
$-4\left(-16\right)+16$
$\sec^2\left(a\right)\cdot\left(\csc\left(a\right)+1\right)$
$\lim_{x\to1}\left(\frac{x^3+1}{x^2+1}\right)^{\frac{3}{x+1}}$
$4x^2\ge4$
$x-2=4$
$y'=-2cos\left(ax\right)$
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